HIGH LEVEL APPROXIMATION FOR IBPS PO AND IBPS CLERK PRELIMS 2018

adminBANK MATH

HIGH LEVEL APPROXIMATION FOR IBPS PO AND IBPS CLERK PRELIMS 2018|| HIGH LEVEL APPROXIMATION PDF HINDI 2018||

Directions: Find the approximate value which should come in place of Question mark (?) in the following question.
दिशानिर्देश: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर आने वाले अनुमानित मूल्य का पता लगाएं।

1 27.003 × 4.99 × (145.003 ÷ 28.97) – (12.001 × 3.94) + 127.03 – 29.14 = ?
A 678
B 725
C 789
D 925
E 806
B
? ≈ 27 × 5 × 145  – 12 × 4 + 127 – 29
29

≈ 135 × 5 – 48 + 127 – 29

= 675 – 48 + 127 – 29

= 802 – 77 = 725

Hence, option B is correct.

2 20.01 × 1024 + 159 = ?2 + 536
A 10
B 16
C 21
D 26
E 35
B

20.01 × 1024 + 159 = ?2 + 536

20 × 1024 + 159 = ?2 + 536

20 × 32 + 159 = ?2 + 536

640 + 159 = ?2 + 536

799 – 536 = ?2

?2 = 263

? = 16.21 ≈ 16

Hence, option B is correct.

3 25.1% of 5902 = ? × 55.96 ÷ 3.82 × 20
A 1
B 2
C 3
D 5
E 7
D

25.1 % of 5902 = ? × 55.96 ÷ 3.82 ×20

= 5902 × 1  = ? × 56 ÷ 4 × 20
4

1476 ÷ 14 ÷ 20 = ?

? = 5.27 ≈ 5

Hence, option D is correct.

4 53.15% of 426 – 30.45% of 745 = ?2 – 512 – 1600
A 08
B 15
C 24
D 27
E 60
C

53.15% of 426 – 30.45% of 745 = ?2 – 512 – 1600

53% of 426 – 30% of 745 = ?2 – 512 – 40

225.78 – 223.5 + 512 + 40 = ?2

?2 = 226 – 223 + 512 + 40

?2 = 555

?2 = 23.55 ≈ 24

Hence. option C is correct.

5 27.031 × 328.001 + 37.081 – ? = 2628.31 + 37.035 – 36.745 × 4.125
A 5008
B 6302
C 6376
D 5306
E 6478
C
27 × 328 + 37 – ? ≈ 2628 + 37 – 37 × 4
Or, ? ≈ (27 × 328 + 37) – (2628 + 37 – 37 × 4) = ( 8856 + 37) – (2665 – 148)
= 8893 – 2517 = 6376
Hence, option C is correct.
6
1535 √35 + 20% of ? – 124.15 of   1  = 6960
9
A 10490
B – 10490
C 15490
D 10590
E 10450
B
1535 35 + 20% of ? – 124.15 of 1  = 6960
9
or, 1535 × 5.916 + ? × 1 – 124 × 1  = 6960
5 9
or, 9071.85 + ?  – 13.77 = 6960
5
Or, ≈ 9072 + ?  – 14 = 6960
5
Or, ?  ≈ 6960 + 14 – 9072 = 6974 – 9072
5
Or, ?  = – 2098
5

Or, ? = – 2098 × 5 = – 10490

Hence, opton B is correct.

7
162.13 × 9 – (10648)  = 5
16 × 14 + 245 + (?)2
A 13
B 16
C 19
D 22
E 25
A
162.13 × 9 – (10648) = 5
16 × 14 + 245 + (?)2
= 1458 – 22  = 5
224 + 245 + (?)2
= 1436  = 5
469 + (?)2

1436 = 5 × (469 + (?)2)

1436 = 2345 + 5 × (?)2

5 × (?)2 = – 909

(?)2 ≈ – 181

(?)2 = 13.452

(?) ≈ 13

Hence, option A is correct
8
(3026.001) + (12.969)2 = ? ÷   6
23.892
A 42
B 45
C 56
D 62
E 67
C
(3026.001) + (12.969)2 = ? ÷ 6
23.892
Or, ? ≈ (3025) + (13)2 × 6
24
Or, ? = (55 + 169) × 6
24
⇒ 224 × 6  = 56
24
Hence, option C is correct
9
25.12 × 152.94 + 5142 – 6336.83  = ?
√360
A 139
B 119
C 209
D 154
E 148
A
25.12 × 152.94 + 5142 – 6336.83  = ?
√360
? = 25.12 × 152.64 + 5142 – 6336.83
√361
≈ 25 ×153 + 5142 – 6337
√360
≈ 3825 + 5142 – 6337
19
= 8967 – 6337
19
= 7630
19

= 138.42 ≈ 139

Hence, option A is correct.
10
82.958 × 22.001 – 16.04 × 3.11  = ?
(9.002)2 –  √145 + (16.997)2
A 1
B 3
C 9
D 7
E 5
E
82.958 × 22.001 – 16.04 × 3.11  = ?
(9.002)2 –  √145 + (16.997)2
= ? 82.958 × 22.001 – 16.04 × 3.11
(9.002)2 –  √145 + (16.997)2
or, ? ≈ 83 × 22 – 16 × 3  = 1826 – 48
81 – √144 + 289 81 – 12 + 289
= 1778  = 1778  = 4.966 ≈ 5
370 – 12  358

Hence, option E is correct.

11 56.99 × 56.02 + 789.998 – 54.9 + 123.33 = ?
A 4560
B 4650
C 4050
D 4540
E 5040
C
56.99 × 56.02 + 789.998 – 54.9 + 123.33
? ≈ 57 × 56 + 790 – 55 + 123
? ≈ 3192 + 790 – 55 + 123
? ≈ 4105 – 55
? ≈ 4050
Hence, option (C) is correct.
12. 35.85% of 569.9 + 35.9% of 450.2 = ?
A 357
B 367
C 377
D 380
E 355
B

35.85% of 569.9 + 35.9% of 450.2

≈ 36% × 570 + 36% × 450

? ≈ 36  × 570 + 36  × 450
100 100

? ≈ 205.2 + 162

? ≈ 367.2

? ≈ 367

Hence, option (B) is correct.

13. √783.99 × √169.123 + 49.9% of 300 = ? × 9.8
A 49
B 51
C 58
D 55
E 60
B

√783.99 × √169.123 + 49.9% of 300 = ? × 9.8

⇒ √784 × √169 + 50  × 300 ≈ ? × 10
100

⇒ 28 × 13 + 150 ≈ ? × 10

⇒ ? ≈ 514  = 51.4
10

⇒ ? ≈ 51

Hence, option (B) is correct.

14 .(7.03)2 + (9.03)2 – 9.88% of 554.99 = ? – 125.01
A 190
B 182
C 175
D 200
E 225
D
(7.03)2 + (9.03)2 – 9.88% of 554.99 = ? – 125.01
⇒ 49 + 81 – 10  × 555 + 125 ≈ ?
100
⇒ ? ≈ 130 – 55.5 + 125 = 199.5
∴ ? ≈ 200
Hence, option (D) is correct.
15 (√1224.889 × 16.23) ÷ 4.99 × 4 = ?
A 504
B 410
C 450
D 362
E350
C

(√1224.889 × 16.23) ÷ 4.99 × 4

? ≈ (√1225 × 16) ÷ 5 × 4

? ≈ 35 × 16  × 4
5

? ≈ 112 × 4 = 448

∴  ? ≈ 450

Hence, option (C) is correct.

 DOWNLOAD PDF HERE